A 47-kg box is being pushed a distance of 8.0 m across the floor by a force whose magnitude is 188 N. The force is parallel to the displacement of the box. The coefficient of kinetic friction is 0.24. Determine the work done on the box by each of the four forces that act on the box. Be sure to include the proper plus or minus sign for the work done by each force.

(a) 1504 J

(b) - 884.35 J

(c) 0 J

(d) 0 J

Explanation:

Mass, m = 47 kg

displacement, s = 8 m

Force, F = 188 N

Coefficient of friction = 0.24

(a) Work done by applied force

W = F s = 188 x 8 = 1504 J

(b) Work done by the friction force

W' = - 0.24 x 47 x 9.8 x 8 = - 884.35 J

(c) Work done by the gravitational force

W''= m g s cos 90 = 0 J

(d) Work done by the normal force

W''' = m g scos 90 = 0 J

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.

i believe the answer is a hope it and is correct