An archer shoots an arrow horizontally at a target 11 m away. the arrow is aimed directly at the center of the target, but it hits 56 cm lower. What was the initial speed of the arrow?

Explanation:

Given :

Distance in the vertical  direction, S = 56 cm

                                                               = 0.56 m

Initial velocity in the vertical direction, u = 0 m/s

Acceleration due to gravity, g = 9.81

Therefore, in order to find the time required,

t = 0.33 seconds

Therefore, the initial velocity of the arrow is given by :

     , where S = 11 m and t = 0.33 seconds

Thus the initial velocity of the arrow is 33.33 m/s.

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answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.