An object of mass 10 kg has a momentum of 15 kg m/s. Find the average force required to accelerate the object to 10 m/s over 20 seconds.

Force = 4.25 Newton

Explanation:

Given the following data;

Mass = 10 kg

Momentum = 15 Kgm/s

Time, t = 20 seconds

Final velocity, V = 10 m/s

To find the average force required;

First of all, we would determine the initial velocity of the object.

Momentum = mass * velocity

15 = 10 * velocity

Velocity = 15/10

Velocity = 1.5 m/s

Next, we would determine the acceleration of the object by using the first equation of motion;

V = U + at

10 = 1.5 + a*20

10 - 1.5 = 20a

8.5 = 20a

Acceleration, a = 8.5/20

Acceleration, a = 0.425 m/s²

Lastly, we would find the average force by using the formula;

Force = mass * acceleration

Force = 10 * 0.425

Force = 4.25 Newton

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .