A bus is moving at a speed of 20 m/s, when it begins to slow at a constant rate of 5 m/s2 in order to stop at a bus stop. If it comes to rest at the bus stop, how far away was the bus from the stop?

40 m

Explanation:

Applying,

v² = u²+2as Equation 1

Where v = final velocity, u = initial velocity, a = deceleration, s = distance

make s the subject of the equation

s = (v²-u²)/2a Equation 2

From the question,

Given: v = 0 m/s (comes to rest), u = 20 m/s, a = -5 m/s² (begins to slow)

Substitute these values into equation 2

s = (0²-20²)/[2(-5)]

s = -400/-10

s = 40 m

Hence the bus was 40 m from the stop

d.7.5cm is your answer

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