A planet of mass m = 4.25 x 1024 kg orbits a star of mass M = 6.75 x 1029 kg in a circular path. The radius of the orbits R = 8.85 x 107 km. What is the orbital period Tplanet of the planet in Earth days? ​

285.3 days

Explanation:

The centripetal force experienced by the planet is the same as the gravitational force so we can write

or

where M is the mass of the star and R is the orbital radius around the star. We know that

where C is the orbital circumference and T is orbital period. We can then write

Isolating , we get

Taking the square root of the expression above, we get

which turns out to be . We can convert this into earth days as

which piece of furniture will have the most inertia and give the furniture movers the most difficulty in moving?  

answer

a 75kg dining table

what is the actual question though?