a point object is 10 cm away from a plane mirror while the eye of an observer(pupil diameter is 5.0 mm) is 28 cm a way assuming both eye and the point to be on the same line perpendicular to the surface find the area of the mirror used in observing the reflection of the point

1.37 mm²

Explanation:

From the image attached below:

Let's take a look at the two rays r and r' hitting the same mirror from two different positions.

Let x be the distance between these rays.

distance between object as well as the mirror

= distance between mirror as well as the eye

Thus, the formula for determining the distance between these rays can be expressed as:

where; the distance between the eye of the observer and the image is:

Then, the tangent of the angle θ is:

replacing into , we have:

x = (0.13157 × 10) mm

x = 1.32 mm

Finally, the area A = π r²

A = 1.37 mm²

c, 1a hope this

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft