find the rate of energy radiated by a man by assuming the surface area of his body 1.7m²and emissivity of his body 0.4​

The rate of energy radiated by the man is 3.86 x  J/s. .

The amount of energy radiated by an object majorly depends on the area of its surface and its temperature. The is well explained in the Stefan-Boltzmann's law which states that:

Q(t) = Aeσ

where: Q is the quantity of heat radiated, A is the surface area of the object, e is the emmisivity of the object, σ is the Stefan-Boltzmann constant and T is the temperature of the object.

To determine the rate of energy radiated by the man in the given question;

= Aeσ

But A = 1.7 m², e = 0.4 and σ = 5.67 x J/s.

So that;

= 1.7 * 0.4 * 5.67 x

     = 3.8556 x

     = 3.86 x  J/s.

Thus, the rate of energy radiated by the man is 3.86 x  J/s. .

Learn more on energy radiation of objects by visiting:

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!