Squids rely on jet propulsion to move around in water. A 1.5 kg squid at rest suddenly expels 0.12 kg of water backward to quickly get itself moving forward at 2.8 m/s. If other forces (such as the drag force on the squid) are ignored, what is the speed with which the squid expels water

The speed of water is 32.2 m/s .

Explanation:

Mass of squid, M = 1.5 kg

mass of water, m = 0.12 kg

velocity of squid, V = - 2.8 m/s

Let the speed of water is v.

Use the conservation of momentum,

Momentum before expelling the water  momentum after expelling water

M x 0 = (M - m) x V + m x v

0 = - (1.5 - 0.12) x 2.8 + 0.12 v

3.864 = 0.12 v

v = 32.2 m/s

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

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