You are given a VHF television antenna (the antenna type is a magnetic loop antenna) and asked to determine the signal strength going into the reciver from the antenna. The antenna is a circular 1-turn loop of diameter 12.9 cm. The magnetic field of the TV signal is perpendicular to the plane of the loop, and is essentially uniform over the area of the loop at any given instant. If the magnetic field is given by B = Bo sin (21 ft) where Bo = 6.9 nT and f = 258.8 MHz (megacycles/sec), the maximum value of the emf induced in the loop, E, is the strength of the signal going into the reciver in mv. What is this signal strength E? mV

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Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.