Object 1 has a mass m1 and a velocity vector v 1 = (2.87 m/s)xhat. Object 2 has a mass m2 and a velocity vector v 2 = (3.06 m/s)yhat. The total momentum of these two objects has a magnitude of 18.6 kg · m/s and points in a direction 66.5° above the positive x-axis. Find m1 and m2.

d. learned preferences i believe is your answer

battery with hi vtge high val resist in series

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .