Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. What is the effective "spring constant" of this simple harmonic motion? Express your answer to three significant digits and include the appropriate units.

We have that the spring constant is mathematically given as

Generally, the equation for angular velocity is mathematically given by

Where

k=spring constant

And

Therefore

Hence giving spring constant k

Generally

Mass of earth

Period for on complete resolution of Earth around the Sun

Therefore

In conclusion

The effective spring constant of this simple harmonic motion is

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568.98

explanation:

its math

the answer would be a