Suppose a 32-pound weight stretches a spring 2 feet. If the weight is released from rest at the equilibrium position, find the equation of motion x(t) if an impressed force f(t) = 24t acts on the system for 0 ≤ t < 5 and is then removed (see Example 5 in Section 7.3). Ignore any damping forces. (Use g = 32 ft/s2 for the acceleration due to gravity.)

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000

can somebody give me the answer so i can graduate