A solenoid consists of N = 130 turns of wire in a coil of length d = 5 cm and cross-sectional area A = 2 cm2. Assume that the magnetic field is uniform inside the solenoid and ignore end effects. Write an equation for the magnetic field B produced by the solenoid. Express the answer in terms of the current through the coil I, the number of turns N, length of the coil d, and the permeability of free space μ0.
Using the equation for the magnetic field determined, calculate the magnetic flux, in webers, through a single loop of the solenoid with a current of I = 2.9 A. The coil is d = 5 cm long and has a cross-sectional area of A = 2 cm2 and consists of N = 130 turns.
The self inductance relates the magnetic flux linkage to the current through the coil. Calculate the self inductance L in units of μH. The coil is d = 5 cm long and has a cross-sectional area of A = 2 cm2 and consists of N = 130 turns.