(a) A pendulum that has a period of 3.00000 s and that is located where the acceleration due to gravity is 9.79m/s2 is moved to a location where the acceleration due to gravity is 9.82m/s2. What is its new period

I assume this is the motion of the simple pendulum

T = 2π ×

=> =

Given T1= 3s g1= 9.79 g2= 9.82

=> T2 = 3.00459 s

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