EASY PHSICS A man jogs at a speed of 1.5 m/s. His dog
waits 2.5 s and then takes off running at a
speed of 2.6 m/s to catch the man.
How far will they have each traveled when
the dog catches up with the man?

At t = 1.6 sec., the man has jogged 1.76m.

From that point on, the dog closes in on the man at the speed of 3.8 - 1.1 = 2.7m/s.

The time for the dog to catch the man is therefore t = 1.76/2.7 = .65s.

The man will have jogged .717m further for a total distance of 2.477m.

The dog will have traveled .65(3.8) = 2.477m.

Explanation:

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