A projectile is launched vertically with an initial velocity of 50 m/s. How long would it take to reach the top of the launch?

It'd take it 5.10 seconds

Explanation:

At the top of the launch, it is maximum height, h

formular derivation :

At maximum height, final velocity, v is zero

From first newtons equation:

v is the final velocity

u is the initial velocity

g is acceleration due to gravity

t is the time taken

but v is zero:

since it is vertical motion, u = usin(theta), where angle is 90°

t is the time taken to reach the top of the launch:

substitute, taking g to be 9.8 m/s²

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.