calcule la energía potencial, en julios y ergios, de una masa de 2 kg que cae de una altura de 9 metros

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.

Answerit increases at a steady rate;

Answermake them get very hot and over time wear them out;

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