The height of a helicopter above the ground is given by h = 3.45t3, where h is in meters and t is in seconds. At t = 2.45 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.

answeralert drivers who drift off the road;