A tube of length L is open at both ends. A stationary wave is set up in this tube when a tuning fork vibrating with frequency f, is held at one end. This is the lowest frequency of stationary wave that
can be formed in this tube.
Another tube of length 2L is closed at one end. A stationary wave is set up in this tube when a
tuning fork vibrating with frequency f, is held at the open end. This is the lowest frequency of
stationary wave that can be formed in this tube
f
frequency
1 a=4
F
2
L
>=22
fie
26
-21
frequency
Fy
ج)
2L
L
14 fy
Assume the end correction for each tube is negligible.
L=
Which equation is correct?

measure their densities same density, same sub

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.