A drag racer starts from rest and accelerates at 43 m/s2. After 2.9 seconds of this constant acceleration, how far down the track is the dragster? (Answer in meters)

180 meters

Explanation:

We know initial position and velocity of the dragster are both zero. We only know acceleration (43 m/s^2) and need to find out how far the dragster moves after 2.9 seconds.

x initial = 0

velocity initial = 0

t=2.9s

a= 43m/s^2

Plug into

180 meters or 1.8 x 10^2 meters is the answer accounting for 2 sig figs.

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