Solve the following two equations for the (positive) time, t, and the position, x. Assume SI units. x = and x = 45.0t + 69.0

real, smaller and upside-down.   so the answer should be b.

a is the best answer your welcome

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j