An object with an acceleration of -6.65m/s squared moves from a rate of 78m/s to 2 m/s. How far will the object have traveled during that interval?​

Approximately .

Explanation:

The acceleration of this object is constant. Hence, the SUVAT equation would apply to the motion of this object. Since the duration of this acceleration is not given, apply the SUVAT equation that does not include time.

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Rearrange this equation to find an expression for displacement, :

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In this question, it is given that the initial velocity is , the velocity after acceleration is , and the acceleration is . Evaluate the expression above to find the displacement of this object:

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the gas collects in coils that then becomes a liquid that then flows through the coils inside the refrigerator

b mirrors submit a iisner? e. for which optical devices does d sometimes have a positive value? o a a and b o b. a and c o c. b and d 0 d. b and cb