What is the acceleration of a rocket that speeds up from 50 m/s to 1000 m/s in 3 seconds?

95 m/s^2

Explanation:

Givens

vi = 50 m/s

vf = 1000 m/s

t = 10 sec

a = ?

Equation

a = (vf - vi)/t

Solution

a = (1000 - 50)/10

a = 950/10

a = 95 m/s^2

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s