1.12 Se ha tendido horizontalmente un cable en la punta de dos postes verticales colocados a 20 m de distancia uno del otro.
Un letrero de 250 N està suspendido del punto medio del
cable y hace que este se pandee en una distancia vertical de
1.2 m. ¿Cuál es la tensión en cada uno de los segmentos del
cable?

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

happy to

pls mark as brainliest

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000