A) total time taken for journey
b) the acceleration during the first part of the journey

Explanation:

a. the total time taken for the journey is 50sec.

b. u=0, v=10m/sec, t=20sec.

a=(v-u)/t = (10-0)/20 = 10/20 = 0.5 m/s².

hope this helps you to solve the problem.

im guessing the west of station b

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s