A plane is flying horizontally with speed 237 m/s at a height 1620m above the ground when a package is dropped for the plane. The acceleration of gravity is 9.8m/s2.What is the horizontal distance from the release point to the impact point. Answer in units of m

1. 0.5g*t^2 = 2010 m.

4.9t^2 = 2010.

t = 20.3 s. = Fall time.

D = Xo*t. = 193m/s * 20.3s = 3909 m.

2. V=sqrt(Xo^2+Yo^2)=sqrt(193^2+58^2) = 202 m/s.

3. Vo*t + 0.5g*t^2 = 2010 m.

58*t + 4.9*t^2 = 2010.

4.9t^2 + 58t - 2010 = 0.

Use Quadratic Formula.

t = 15.2 s. = Fall time.

D = 193m/s * 15.2s = 2934 m.

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