Calculate the acceleration of the two masses shown in the picture above. A. 0.77 m/s^2
B. 3.92 m/s^2
C. 8.62 m/s^2
D. 5.91 m/s^2

Hello!

We can begin by summing the forces acting on each mass. (Tension is CONSTANT because the string is both frictionless and massless).

On the 3 kg block: (Ignore forces acting in the vertical direction since there is no motion in that axis)

∑F = -M₁gsinФ + T

On the 8 kg block:

∑F = -T + M₂g

Sum the forces:

∑F = -M₁gsinФ + T -T + M₂g

∑F = -M₁gsinФ + M₂g

Divide by both masses to get the acceleration:

Plug in values: (g = 10m/s²)

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.