A 1kg apple and a 8 kg apple falls from a height of 10m ,find the time taken by them to fall at ground if no external force acts on it except gravity. (take g=10m/s²)

An apple of 1 kg is dropped from 10.0m. How long does it take to hit the ground?

List the known and unknown quantities from the question.

u = initial velocity = 0 m/s

s = displacement = -10.0 m

g = acceleration due to gravity = -9.8 m/s²

t = time interval = ? s

Use the following kinematic equation.

s = ut + ½gt²

Since u = 0 m/s, ut = 0, and the equation can be rewritten.

s = ½gt²

Solve for t.

t² = 2s/g

t = √(2s/g)

t = √(2 × (-10.0 m))/(-9.8 m/s²)

t = √(-20.0 m)/(-9.8 m/s²) = 1.4 s

An apple of 8 kg is dropped from 10.0m. How long does it take to hit the ground?

mgh = 1/2×mv 2

wher m is the mass of the body v is velocity and g is acceleration due to gravity and h is the height

2gh=v 2

2×9.8×10 = v 2

v 2 = 196

v= 14m/s

T=v/g=1.4s

By any way you solve there is no role of mass here

answer: b.

explanation:

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: