An object 2.5kg is released from a height of 5m above the ground. Calculate the velocity of the object just before it strikes the ground.

measuring things 1 litre of water

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

not too sure thinking all accelerations are pointed down

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