(part 1 of 2): An airplane flying parallel to the ground undergoes two consecutive displacements. The first is 84 km at 33.7◦ west of north, and the second is 160 km at 65.3◦ east of north. What is the magnitude of the plane’s total displacement? Answer in units of km.

(part 2 of 2): At what angle east of north is the plane’s total displacement? Answer in units of ◦.

The answer is b.the gaseous state is electrically positive, while the plasma state is electrically negative. 

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.