Two antiparallel forces with equal magnitudes Fi and F2 are applied to the uniform rod as shown in figure. Take point O as the axis of rotation. (Assume the
weight of rod is negligible)

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west