2. A 6.0 kg mass is pulled along a horizontal surface where the coefficient of friction is 0.20. a) What is the friction force acting on the mass?
b) What force is needed to accelerate it at 0.68 m/s^(2)?

Below

Explanation:

a) To find the force of friction acting on the mass we can use this formula :

     friction = coefficientoffriction x normal force

First we need to find the normal force of this object :

     Fn = mg

          = (6.0)(9.8)

          = 58.8 N

Now we can find the force of friction acting on the object :

     friction = (0.20)(58.8N)

                 = 11.76 N

                 = 12 N (we round this to 2 sig figs)

b) To find the force needed to accelerate this object at 0.68 m/s^2 use this :

     F = ma

     0.68 = x - 11.76 / 6

     x = 15.84

     x = 16 N

Hope this helps! Best of luck <3

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this