A plane flying due north at 191 mph encounters winds that blow the plane due east at 45 mph. Determine the plane's resultant velocity. Record your answers to the nearest tenth.

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Explanation:

For these types of questions, you should draw out your triangles and resultant vectors.

For this, we can use the pythagorean theorem to solve this :

     vpf^2 = vpi^2 + vw^2

     vpf^2 = 45^2 + 191^2

     vpf =

     vpf = 196.2294

     vpf = 200 mph

Now we need to find the angle of the plane's direction using soh cah toa

     Tan(x) = O / A

              x = tan^-1(191/45)

              x = 76.74

              x = 77 degrees

Therefore, the plane's result velocity is 200 mph [ E 77 N ]

Hope this helps!

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

answer///terminator or twilight zone;