Consider two random variables X and Y It is always true that H(X) ≤ H(X|Y ) It is always true that H(X) ≥ H(X|Y ) It is always true that H(X) ≥ 2 H(X|Y ) One cannot compare H(X) and H(X|Y )

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by