Mountain goats can easily scale slopes angled at 60∘ from horizontal. What is the static friction force acting on a mountain goat that weighs 750 N and is standing on such a slope? I know the formula for static friction is Fs = coef of static friction * Normal Force
But I can't find the formula for the coeffecient.

Explanation:

Let's assume that the x-axis is aligned with the slope and the (+)-direction is pointing down the slope. Now let's apply Newton's 2nd law to this problem:

(1)

(2)

where W is the weight of the mountain goat, N is the normal force and is the frictional force. Using Eqn(1), we see that the frictional force is

Bonus:

If you want to solve for the coefficient of static friction rewrite Eqn(1) as

(3)

From Eqn(2), we see that

Put this result back into Eqn(3) and we get

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.