If a man with mass 70 kg, standing still, throws an object with mass 5 kg at 50 m/s, what will be the recoil velocity of the man, assuming he is standing
on a frictionless surface?
A. -3.6 m/s
B. O m/s
C.3.6 m/s
O D. 50.0 m/s

-3.6 m/s

Explanation:

Here we need to use the conservation of momentum law.

So, the momentum of the man initially is zero and so of the object. The momentum of the object after throw is 5 kg multiplied by 50 m/s which is 250 kg m/s.

So the equation is as follows:

0 + 0 = (250 + 70 x v) kg m/s

Which leads to v = (-250/70) m/s ≈ - 3.6 m/s

I am not 100 % sure though! Hope this helps! :)

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

are you like autistic or something?

xd