Complete the last column of the table below. Use another sheet of paper for your answer. Planet Period (y) Semi-major axis (m) T2/R3 (y2/m3) Mercury 0.241 5.79x1010 Venus 0.615 1.08 x1011 Earth 1 1.50 x1011 Mars 1.88 2.28 x1011 Jupiter 11.9 7.78 x1011 Saturn 29.5 1.43 x1012 Uranus 84 2.87 x1012 Neptune 165 4.50 x1012 Pluto 248 5.90 x1012

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.