An electron starts from rest. A horizontally directed electric field accelerates the electron through a potential difference of 37V. The electron then leaves the electric field and moves into a magnetic field. The magnetic field strength is 0.26T, directed into the page, and the mass of an electron is 9.11x10kg. a) Determine the speed of the electron at the moment it enters the magnetic field.
b) Determine the magnitude and direction of the magnetic force on the electron.
c) Determine the radius of the electrons circular path. x ſty 100 X B

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j