How class iv differs from class iii is based solely

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Answerdecrease; intensify

The answer is  the gravitational potential energy it had from being above the ground is converted to kinetic energy as the rock falls. as kinetic energy increases, the velocity of the rock will also increase. however, if one considers the air, the rock will lose energy as it falls due to air resistance. if the cliff is high enough, the acceleration due to gravity and the air resistance due to the velocity will be exactly equal and there will be no change in kinetic energy.  hope its and mostly important have a nice day ; )