Two students push a 20.0\,\text{kg}20.0kg20, point, 0, start text, k, g, end text desk from opposing directions. One student pushes with a force of 5.0\,\text{N}5.0N5, point, 0, start text, N, end text to the left, and the other student pushes with a force of 2.0\,\text{N}2.0N2, point, 0, start text, N, end text to the right. Calculate the horizontal acceleration of the desk.

This did i unseated, sorry

"induction" is the process of charging an object without touching it.hope my answer has you : )

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge