A solenoid with 200 turns has a radius of 0. 040 m and is 40 cm long. If this solenoid carries a current of 12 a, what is the magnitude of the magnetic field near the center of the solenoid?.

The particles of the gas inside the ball heats up, bouncing off each other and spreading farther apart.hope my answer has you : )

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.