Va A rail wagon of mass 5000 kg moving at a velocity
of 1.6 ms-1 collides with a
stationary wagon of mass
3000 kg (see Figure 4). After
the collision, the 3000 kg wagon
moves away at a velocity of
1.5 ms-1. Calculate the speed
and direction of the 5000 kg
wagon after the collision.

0.7m/s

Explanation:

According to the conservation of linear momentum, the moment before a collision is equal to the moment after the collision. The equation is written as follows: , where is the mass of the object, is the initial velocity, and is the final velocity.

Let's say the object is our moving wagon and the object is our stationary wagon. ,  , since the wagon is stationary, it doesn't have any initial velocity. After collision, the mass remains the same, but the velocity changes:

We can observe that is what we're looking for according to the question. Now let's substitute our values.

= 0.7m/s

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂