A student on a bicycle decided to determine his acceleration when coasting down a steep hill. The student started from a full stop and reached a velocity of 8.75 m/s in 3.8 s. What was his average acceleration? Assume that downhill is the positive direction.

A=2.2

Explanation:

You have to lay everything out first.

You are given the:

Velocity and the time

V=8.75m/s

t=3.8s  

Now you need to know what you are looking for, and that is the average acceleration.

Write down the formula (teachers like this)

A=v/t

Now calculate:

8.75/3.8= 2.3026315789473

You can now round down since the number next to the decimal is below 5

The number of significant digits will be 2 because that is the lowest number in the question. This means you will only need to display 2 numbers.

The final answer will be:

A=2.2

:)

*make sure to show your work step by step, some nice teachers give extra marks for that*

I hope this helped, goodluck! :D

its c its is a mixture of gases

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.