A train starts from rest and accelerates uniformly until it has traveled 5.6 km and acquired a velocity of What is the approximate acceleration of the train during this time?

you need add the numbers

Explanation: you need to add the numbers

0.16 m/s²

Explanation;

From one of the equation of linear motion;

vf2 - vi2 = 2ax

Where;

vf = final speed after traveling a distance x at constant acceleration; vf = 42 m/s

vi = initial speed = 0 (starts from rest)

a = constant acceleration while traveling a distance x

x = distance traveled at constant acceleration; x = 5.6 km = 5600 m

Therefore;

a = vf2/(2x)

 = 422/(2*5600) m/s²

 = 0.1575 m/s²

  ≅ 0.16 m/s²

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the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: