A driver starts his parked car and within 6.0 seconds, reaches a velocity of 54.0 km/h. What is his acceleration, in m/s2?

Explanation:

a = Δv/t

54.0 km/h(1000 m/km / 3600 s/hr) = 15.0 m/s

a = (15.0 - 0.00) / 6.0

a = 2.5 m/s²

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.