I m² of water at T-15 °C (specific heat 4186 J/Kg C) is reversed in a copper container of 0.5 Tons exposed to direct sun and having reached a temperature of 120 ° C (specific heat 390 J/Kg C). Does the water boil up? Why?

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

An atom's smaller negative particles are at a distance from the central positive particles, so the negative particles are easier to move.