General kinematics problem. "Anna is returning from vacation driving down the Sunshine Highway. She travels for a stretch (SA) at a speed of 110 km/h. Then, due to an increase in traffic, Anna is forced to reduce her speed by travelling the second part of the journey (SB) at 60 km/h. The total distance and duration of the trip are 350 km and 4.0 hours respectively.
-> Calculate the time intervals needed to travel SA and SB
-> Calculate the distances covered in the two sections SA and SB".

The results I should get by doing the exercise are in the attached picture.

If you could explain the various steps in the problem you would be doing me a huge favor. Thanks!

Explanation:

Ciao compagno italiano. Scriverò in inglese perchè i moderatori diventano noiosi e iniziano a bannare.

Va = 110 km/h

Vb = 60 km/h

Stot = 350 km

Ttot = 4h

We can write: (I am completing)

Look at the screenshots. You see how we calculated Tb (the time for going with the speed of Vb to the end of the road).

Now that we know Tb we can easily calculate Ta thanks to the relation: Ta + Tb = 4h.

After that, for calculating the distances, we just use the (leggi orarie del moto rettilineo uniforme, I don't know how they're called in English): S = VT.

And that's it. We'll consider the initial displacement (S_0) equal to 0 as there is no need in this problem.

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okay, ima .

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a) the event horizon, singularity, and the chute located between the two.