A fly undergoes a displacement of -5. 80 m while accelerating at -1. 33 m/s for 4. 22 s what was the initial velocity of the fly.

The fly has an average velocity of

v[ave] = ∆x/∆t = (-5.80 m) / (4.22 s) ≈ -1.37 m/s

If its acceleration is constant, then its average velocity is also equal to the average of its initial and final velocities,

v[ave] = (v[initial] + v[final]) / 2

which tells us that

v[initial] ≈ -1.37 m/s - 1/2 v[final]

The fly's final velocity after some time t is given by

v[final] = v[initial] + (-1.33 m/s²) t

so that after 4.22 s, we have

v[final] ≈ v[initial] - 5.61 m/s

Substitute this into the equation for v[initial] :

v[initial] ≈ -1.37 m/s - 1/2 (v[initial] - 5.61 m/s)

Solve for v[initial] :

3/2 v[initial] ≈ -1.37 m/s + 1/2 (5.61 m/s)

⇒   v[initial] ≈ 0.955 m/s

weather forecasts are done by collecting data about the current state of the atmosphere mainly the temperature, humidity and wind and using meteorology, to determine the atmosphere that evolves over time. the h and l mean the high and low pressure. the red strip is a warm front. the blue strip is a cold front. the blue and red strip is a stationary front. the purple strip is a occluded front.

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