A ring of radius a contains a charge q distributed uniformly over its length. find the electric field at a point on the axis of the ring at a distance x from the centre?

case 1: x < a

then q = 0 therefore E = 0

case 2: x > a or x = a

here q has a value and it is distributed over the length of the ring so,

then the electric field equal

Explanation:

as Gaus law states, if x < a there will be no charge therefore there will be no electric field.

but if x = a or x > a the there will be a charge q and as it's distributed over the length it will equal lambda as shown above, then the electric field will equal lambda over 2 pi epsilon node multiplied by the radius a.

hope this helps ❤.

Hey There!

Let's solve.....

Refer to attachment...

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

the total distance traveled by the car is

30km + 49km = 79 km .