A dart player throws a dart horizontally at a velocity of 12.7 m/s. The dart hits the board 0.39 m below the height from which it was thrown.
How far away is the player from the board? Provide evidence.

Answer

Explanation:

It is given that,

The horizontal speed of a dart player =

12.4 m/s

The dart hits the board 0.32 m below the

height from which it was thrown.

We need to find how long it take the dart

to hit the board.

Let the time taken by the dart to hit the

board. Using second equation of motion

to find it.

1

y = ut +

2

=

at2

Put u = 0 and a=-g

-

-1

y =

1942

1

-0.32

=

x 9.8t2

2

2 x 0.32-0.32

=

t=

9.8

t= 0.255 s

Let x be the horizontal distance travelled.

It is calculated as follows:

X =

12.4 x 0.255

=

= 3.16 m

So, the dart will hit the board at a

distance of 3.16 m.

Muscardinus • Quality

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.

true tan speed = ang vel x radius